-((44)(225))/(v^2)+15+6=10

Solution for -((44)(225))/(v^2)+15+6=10 equation:

-((44)(225))/(v^2)+15+6=10

We move all terms to the left:

-((44)(225))/(v^2)+15+6-(10)=0


Domain of the equation: v^2!=0

v^2!=0/

v^2!=√0

v!=0

v∈R


determiningTheFunctionDomain
-44225/v^2+15+6-10=0

We add all the numbers together, and all the variables

-44225/v^2+11=0

We multiply all the terms by the denominator


11*v^2-44225=0

We add all the numbers together, and all the variables

11v^2-44225=0

a = 11; b = 0; c = -44225;
Δ = b2-4ac
Δ = 02-4·11·(-44225)
Δ = 1945900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1945900}=\sqrt{100*19459}=\sqrt{100}*\sqrt{19459}=10\sqrt{19459}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{19459}}{2*11}=\frac{0-10\sqrt{19459}}{22}
=-\frac{10\sqrt{19459}}{22}
=-\frac{5\sqrt{19459}}{11}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{19459}}{2*11}=\frac{0+10\sqrt{19459}}{22}
=\frac{10\sqrt{19459}}{22}
=\frac{5\sqrt{19459}}{11}
$